A stone is dropped from a tower 100 meters above the ground. The stone falls past ground level and into a well. It hits the water at the bottom of the well 5.00 seconds after being dropped from the tower. Calculate the depth of the well. Given: g = -9.81 meters/second2.
Let's use the second kinematic equation, and define the depth of the well as y and 0 as the ground level. Δy = v₀t + 1/2gt² y-100 = 0(5) + 1/2(-9.8)(5)² y-100 = -4.9(25) = -122.5 y = -22.5
