Respuesta :
Which equation models the relationship? Answer: w=50-2.5t
Is there a viable solution when time is 30 minutes? Answer: No, the tub will be empty by then.
This is a linear relationship. The slope-intercept form of the linear equation is:
[tex]y=mx+c[/tex]
Where,
- m is the rate of change (positive if increasing rate and negative if decreasing rate)
- c is the y intercept, or the initial value
Rate of change is 2.5 quarts per minute (it is decreasing so m is -2.5)
Initial value is 50 quarts, so c is 50.
Plugging in the values we get [tex]y=-2.5x+50[/tex].
Changing variables to w instead of y and t instead of x, gives us,
[tex]w=50-2.5t[/tex]. Where w is warts of water left in the tub and t is the time in minutes.
There is no viable solution when t=30 because at t=20, w=0 ([tex]0=50-2.5(20)[/tex]). It means after 20 minutes, there is no water left. So t=30 minutes doesn't make sense.
ANSWER:
Modelling equation: [tex]w=50-2.5t[/tex]
When [tex]t=30[/tex], there is no VIABLE solution