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A fantasy board game makes use of four dice. The first is a standard 6-faced die, the second die has 4 faces, and the other two have 10 faces each. If all the dice are thrown together and their combination dictates a certain outcome of the game, how many possible outcomes exist?


30



240



2,400



3,000

Respuesta :

AlexisSchafer01
2,400 would be the best outcome

JeanaShupp

Answer: 2,400

Step-by-step explanation:

Number of possible outcomes on a standard 6-faced die =6  (Equal to the number of faces on die)

Similarly, Number of possible outcomes on a standard 4-faced die =4

Number of possible outcomes on a standard 10-faced die =10

We apply the Fundamental principal of counting, that says that the total number of outcomes for a number of events is equal to the product of the possible outcomes of each event.

We get, the number of possible outcomes exist :-

[tex]6\times4\times10\times10\ \ \ [\ \because\ \text{ one 6-faced, one 4-faced and two 10-faced die]}[/tex]

[tex]=2400[/tex]

Hence, the number of possible outcomes exist =2,400

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