A cylindrical water tank is being filled with a hose. The depth of the water increases by 1 1/4 feet per hour.

How many hours will it take for the water level in the tank to be 3 1/2 feet deep?

Enter your answer as a mixed number in simplest form

Respuesta :

Answer: 2 4/5

Your answer would be 2 4/5. Hope this helps.

Step-by-step explanation:

Answer: [tex]2\frac{4}{5}[/tex] hours

Step-by-step explanation:

Given: The rate of increase of depth of water = [tex]1\frac{1}{4}=\frac{5}{4}[/tex] feet per hour.

Depth = [tex]3\frac{1}{2}\ =\frac{7}{2}\ feet[/tex]

Let h be the number of hours the water level in the tank to be [tex]3\frac{1}{2}[/tex] feet deep.

We know that the rate of change of depth of water with respect to time is given by :-

[tex]k=\frac{\text{Depth}}{\text{time}}\\\\\Rightarrow\ \frac{5}{4}=\frac{\frac{7}{2}}{h}\\\\\Rightarrow\ \frac{5}{4}=\frac{7}{2h}\\\\\Rightarrow5(2h)=4(7)\\\\\Rightarrow h=\frac{28}{10}=\frac{14}{5}=2\frac{4}{5}[/tex]

Hence, it will take [tex]2\frac{4}{5}[/tex] hours for the water level in the tank to be [tex]3\frac{1}{2}[/tex] feet deep.