An ant crawls at a rate of 2 1/6 feet per minute.
At this rate, how long does it take the ant to crawl a distance of 5 1/5 feet?
Enter your answer as a mixed number in simplest form in the box.

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Answer:

[tex]2\frac{2}{5}\ minutes[/tex]

Step-by-step explanation:

Convert mixed number to an improper fractions first

[tex]2\frac{1}{6}\frac{ft}{min}=\frac{2*6+1}{6}=\frac{13}{6}\frac{ft}{min}[/tex]

[tex]5\frac{1}{5}\ ft=\frac{5*5+1}{5}=\frac{26}{5}\ ft[/tex]

By proportion

[tex]\frac{(13/6)}{1}\frac{ft}{min} =\frac{(26/5)}{x}\frac{ft}{min}\\ \\ x=(26/5)/(13/6)\\ \\x=156/65\ min[/tex]

Convert to mixed number

[tex]\frac{156}{65}\ min=\frac{130}{65}+\frac{26}{65}=2+\frac{26}{65}=2+\frac{2}{5} =2\frac{2}{5}\ min[/tex]

The rate of speed is the rate at which the total distance is traveled in the time taken. The time taken by the ant to crawl a distance of  [tex]5\dfrac{1}{5}[/tex] feet is  [tex]2\dfrac{2}{5}[/tex] minutes.

What is rate of speed?

The rate of speed is the rate at which the total distance is traveled in the time taken. Rate of speed can be given as,

[tex]s_r=\dfrac{x}{t}[/tex]

Here, [tex]x[/tex] is the distance traveled by the object and [tex]t[/tex] is time taken but the object to cover that distance.

Given information-

The rate of speed of crawl of ant is [tex]2\dfrac{1}{6}[/tex] feet per minute.

Total distance is [tex]5\dfrac{1}{5}[/tex] feet.

As the total distance is [tex]5\dfrac{1}{5}[/tex] feet and the rate of speed of the crawl of ant is [tex]2\dfrac{1}{6}[/tex] . Hence the time can be calculated using above formula as,

[tex]s_r=\dfrac{x}{t}[/tex]

Put the values,

[tex]2\dfrac{1}{6} =\dfrac{5\dfrac{1}{5} }{t}[/tex]

[tex]\dfrac{13}{6} =\dfrac{\dfrac{26}{5} }{t}[/tex]

Solve for [tex]t[/tex],

[tex]t=\dfrac{26}{5} \times\dfrac{13}{6} \\t=\dfrac{26}{5}\\t=2\dfrac{2}{5}[/tex]

Hence the time taken by the ant to crawl a distance of [tex]5\dfrac{1}{5}[/tex] feet is [tex]2\dfrac{2}{5}[/tex] minutes.

Learn more about the rate of speed here;

https://brainly.com/question/359790