Montly salary = 1200 + 3% * price = 1,200 + 0.03p
a) price = 72,000 => 1200 + 3%* 72,000 = 1200 + 0.03*72,000 = 3,360
Answer 1: 3,360
b) salary = 6,000 => 6,000 = 1,200 + 0.03p => p = [6000 - 1200] / 0.03 = 160,000
Answer 2: 160,000
c) linear equation
salary = y; price = x
y = 1200 + 0.03x
Answer 3: y = 1200 + 0.03x
d) graph
- slope: is the coefficient of the independent variable, x: 0.03
It means the increase of salary per unit of price of the vehicles sold
- y intercept: it is the constant value of the linear equation: 1200
It represents the salary if Sid does not sell any vehicle.
- The graph is a straight line: y = 1200 + 0.03x
- You can use two points to draw the line.
- Use x = 0, for which y = 1200 and
x = 100,00 for which y = 1200 + 0.03*100,000 = 1200 + 30,0000 = 31200
- Use an adequate scale. I suggest that every division of the x-axis be $10,000 or $20,000; and every division of the y-axis be $1000
