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Estimate the number of gallons of gasoline consumed by the total of all automobile drivers in the U.S., per year. Suppose that there are about 3 × 10^8 people in the United States, approximately half of the them have cars, each car drives an average of 12,000 mi per year, and consumes a gallon of gasoline for each 20 mi?

Respuesta :

3 x 108 is roughly 300 people. Half of them have cars. Half of 300 = 150. 150 x 12000 = 1,800,000 miles driven. Each car gets 20mpg. Solve for the # of gallons consumed.
Chlidonias

Answer:

[tex]G = 9 \times 10^{10} gallons[/tex]

Explanation:

Total number of people in US is  [tex]N_p = 3 \times 10^8[/tex]

Only half of them have cars. So, Number of cars in US

[tex]N_C = \frac{N_p}{2} \\\\N_C = \frac{3 \times 10^8}{2} \\\\N_C = 1.5 \times 10^8[/tex]

Each cars drives 12000 miles, so total distance travelled by all of these cars combined

[tex]D = N_C \times 12000\\\\D = 1.5 \times 10^8 \times 12000\\\\D = 1.8 \times 10^{12} miles[/tex]

To travel 20 miles, we need 1 gallon of gasoline

Amount of gasoline required to travel one mile is  [tex]\frac{1}{20}[/tex] gallons

Amount of gasoline required to cover the distance 'D'.

[tex]G = D \times \frac{1}{20} \\\\G = 1.8 \times 10^{12} \times \frac{1}{20} \\\\G = 9 \times 10^{10} gallons[/tex]

Amount of gasoline required to cover the distance 'D'.

[tex]G = D \times \frac{1}{20} \\\\G = 1.8 \times 10^{12} \times \frac{1}{20} \\\\G = 9 \times 10^{10} gallons[/tex]