contestada

Calculate the molarity of the solution: 6.02x10^22 molecules of HCl (molecular weight = 36.5 g/mole) in 2.0 liters of water.

Respuesta :

SapphireMoon
6.02x10^22 is one mole, so we can just say it's 1 mol HCl in 2.0 L of water. Molarity is mol/L, so 1 mol/2 L is 0.5 mol/L or 0.5 M. Make sense?

Answer:

Molarity of HCl = 0.05 M

Explanation:

Given:

Molecules of HCl = 6.02*10^22

Molecular weight of HCl = 36.5 g/mole

Volume of water = 2.0 L

Explanation:

Molarity of a solution is the number of moles of solute in a given volume (liter) of the solution.

[tex]Molarity = \frac{Moles}{Volume}[/tex]

Calculation:

1 mole of HCl contains 6.023*10^23 molecules

Therefore, 6.02*10^22 molecules corresponds to :

=[tex]\frac{6.02*10^{22} }{6.023*10^{23} } =0.1\ moles\ HCl[/tex]

[tex]Molarity\ of\ HCl = \frac{moles\ HCl}{Vol} = \frac{0.1\ moles}{2.0 \ L} =0.05M[/tex]

Otras preguntas