Respuesta :

52=±31−u22−−−−−+4u2 36(1−u22)=25−80u2+64u22 100u22−80u2−11=0 u2=4±33√10≈−0.120or0.920 u1≈−0.393or0.993 i.e. the solutions are⟨−0.393,0.920⟩ and ⟨0.993,−0.120⟩