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A running track in the shape of an oval is shown. The ends of the track form semicircles.


What is the perimeter of the inside of the track?

(π = 3.14)

A - 392.00 m
A - 372.22 m
A - 444.44 m
A - 588.88 m

P.S. I attached a file here to look at the oval.

A running track in the shape of an oval is shown The ends of the track form semicircles What is the perimeter of the inside of the track π 314 A 39200 m A 37222 class=

Respuesta :

I would think 444.44 ._. Do you go to FLVS? ;-; cause im on the test to xD

calculista

Answer:

The perimeter of inside of the track is [tex]444.44\ m[/tex]

Step-by-step explanation:

we know that

The perimeter of the oval is equal to the circumference of a circle (two semicircles is equal to one circle) plus the length of [tex]150\ m[/tex] multiplied by [tex]2[/tex]

Find the circumference of a circle

The circumference of a circle is equal to

[tex]C=\pi D[/tex]

we have

[tex]D=46\ m[/tex]

substitute the values

[tex]C=(3.14)(46)=144.44\ m[/tex]

Find the perimeter of the oval

[tex]144.44\ m+2*150\ m=444.44\ m[/tex]

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