aryannamulgado
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The table and the graph below each show a different relationship between the same two variables, x and y:

*insert attached picture here*

How much more would the value of y be on the graph than its value in the table when x = 12?

I added the y values for both until i got twelve and I subtracted the table's final y value from the graph's. I ended up with 410 but the only answer choices are:

150
300
450
600

What am I doing wrong?

The table and the graph below each show a different relationship between the same two variables x and y insert attached picture here How much more would the val class=

Respuesta :

ok well i had this problem on a quiz haha i forgot wha i did exacally but i can solve it. so where you start is you find what the table will equal at 12 and thats 360 so you got that right by multiplying 5 times 30 and getting 150, then you added 150 to 210. after that yo will want to find out what the graph will equal so you would want to 8 from 12 and you would get 4.

If you see the graph goes up by 2s so you need to see how much it goes up in 2 times and split that in half. so you find that it goes up 110 in 2 times so you split that in half and get 55. so then you will multiply 55 (how many times it goes up once) by 4 (how many times you will get to be to 12) When you multiply that you will get 220.

So your chart equals 360 and your graph equals 220. If you subtract both of those you get 120. so that would be your answer

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