Answer: The correct answer is option b.
Explanation: We are given that the rocket is at rest initially final velocity is 445m/s.
The acceleration of the rocket is [tex]99.0m/s^2[/tex]
To calculate the distance of rocket, we use third equation of motion, which is:
[tex]v^2-u^2=2as[/tex]
where, v = final velocity = 445m/s
u = initial velocity = 0m/s
a = acceleration = [tex]99m/s^2[/tex]
s = distance = ? m
Putting values in above equation, we get:
[tex](445)^2-(0)^2=2(99)s\\\\s=1\times 10^3meters[/tex]
