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Which sequence could be used to prove that AD = BC?


First prove ABC is congruent to CDA, and then state AD and BC are corresponding sides of the triangles.First prove ABC is similar to CDA, and then state AD and BC are opposite sides of the parallelograms.First prove ABCD is congruent to CDAB, and then state  AD and BC  are corresponding sides of two parallelograms.First prove ABCD is similar to CDAB, and then state  AD and BC are opposite sides of the parallelograms.

Which sequence could be used to prove that AD BCFirst prove ABC is congruent to CDA and then state AD and BC are corresponding sides of the trianglesFirst prove class=

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MissPhiladelphia
I believe that the best answer among the choices provided by the question is First prove ABC is congruent to CDA, and then state AD and BC are corresponding sides of the triangles.
Hope my answer would be a great help for you.    If you have more questions feel free to ask here at Brainly.

The sequence could be used to prove that AD = BC are corresponding sides of two parallelograms.

Given that,

We have a parallelogram ABCD to CDAB.

We have to prove that ,

AD and BC are opposite sides of the parallelograms.

According to the question,

In the given picture, we have a parallelogram ABCD with diagonal AC.

AB║ CD, AD║BC

Now, By its diagonal AC it is divided in two triangles ΔABC and ΔADC,

∠ACB =∠DAC  and ∠CAB = ∠ACD  [alternate interior angles]

Alternate interior angles are the angles formed on the opposite sides of the transversal.

Reflexive property of equality states that a number is always equal to itself.

AC=AC  {Reflexive property}

∴ By ASA postulate of congruence ,

Δ ABC ≅  Δ ADC

AD = BC [corresponding sides of the congruent triangles are congruent]

Hence proved ,The sequence could be used to prove that AD = BC are corresponding sides of two parallelograms.

For the more information about Parallelogram click the link given below.

https://brainly.com/question/22106495

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