Respuesta :

Answer:

x = 1 and y = -8/3

step-by-step explanation:

  • In order to solve this, insert equation 1 into 2

solve for x

[tex]\sf 6x+3\left(\frac{4}{3}x-4\right)=-2[/tex]

[tex]\sf 6x+4x-12=-2[/tex]

[tex]\sf \rightarrow 10x = -2 +12[/tex]

[tex]\sf \rightarrow 10x = 10[/tex]

[tex]\sf \rightarrow x = 1[/tex]

solve for y

[tex]\hookrightarrow \sf y = \frac{4}{3} x-4[/tex]

[tex]\hookrightarrow \sf y = \frac{4}{3} (1)-4[/tex]

[tex]\hookrightarrow \sf y=-\frac{8}{3}[/tex]

Answer:

x=1 and y=-8/3

Step-by-step explanation:

The easiest way to solve this is by substitution because the first equation is already in slope-intercept form.

First, take y= 4/3x -4 and substitute it into the second equation as follows: 6x + 3(4/3x -4) = -2

Next, simplify that equation to get 6x + 12/3x -12 = -2.

After that, combine all like values: 10x - 12 = -2.

Finally, add 12 to each side and divide by 10 to get x=1.

To find the y-value, substitute x=1 into either equation and solve for x (I'm choosing the first equation). y= 4/3(1) -4

In order to make simplifying this easier, I find that -4 = -12/3.

Finally, simplify: y= 4/3 - 12/3 = -8/3.

The solution to the system of equations is (1, -8/3), or x=1 and y=-8/3.