HELP ASAP PLEASE!!!! :(

Answer:
x = 1 and y = -8/3
step-by-step explanation:
solve for x
[tex]\sf 6x+3\left(\frac{4}{3}x-4\right)=-2[/tex]
[tex]\sf 6x+4x-12=-2[/tex]
[tex]\sf \rightarrow 10x = -2 +12[/tex]
[tex]\sf \rightarrow 10x = 10[/tex]
[tex]\sf \rightarrow x = 1[/tex]
solve for y
[tex]\hookrightarrow \sf y = \frac{4}{3} x-4[/tex]
[tex]\hookrightarrow \sf y = \frac{4}{3} (1)-4[/tex]
[tex]\hookrightarrow \sf y=-\frac{8}{3}[/tex]
Answer:
x=1 and y=-8/3
Step-by-step explanation:
The easiest way to solve this is by substitution because the first equation is already in slope-intercept form.
First, take y= 4/3x -4 and substitute it into the second equation as follows: 6x + 3(4/3x -4) = -2
Next, simplify that equation to get 6x + 12/3x -12 = -2.
After that, combine all like values: 10x - 12 = -2.
Finally, add 12 to each side and divide by 10 to get x=1.
To find the y-value, substitute x=1 into either equation and solve for x (I'm choosing the first equation). y= 4/3(1) -4
In order to make simplifying this easier, I find that -4 = -12/3.
Finally, simplify: y= 4/3 - 12/3 = -8/3.
The solution to the system of equations is (1, -8/3), or x=1 and y=-8/3.