How many grams are in 6.04 x 10 22 particles of AICI3

Answer:
333.415 grams
Explanation:
If you multiply and do a few calculations, this is the answer :)
333.415 grams
Your general equation is Al + 3Cl -> AlCl3
A mole of Aluminum weighs 26.98 grams.
26.98 x 2.5 = 67.45 (so that is the weight of the aluminum in your AlCl3 compound.
Now lets add the weight of the Cl.
the molar mass of chlorine is 35.45 grams/mole.