Answer:
Explanation:
Mica dielectric constant (k) is approximately 3. The distance between the plates is 5 mm = [tex]5\times10^{-3}[/tex] m = d and the area of each plate is[tex]A = 0.1\times 0.2=2\times 10^{-2} m^{2}[/tex]. So, the capacitance of that capacitor is:
[tex]C=\frac{\epsilon_{0}kA}{d}=\frac{(8.85\times10^{-12})(3)(2\times10^{-2}}{5\times10^{-3}}=10.62\times10^{-11} =1.062\times10^{-10} F[/tex]
or approximately 0.106 nF.
