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If you were to repeat this experiment using an entire 16.5 g beer can and get the
same percent yield, what mass of alum would you expect? (I got .126% yield)

Respuesta :

okpalawalter8

The mass of alum  expected is mathematically given as

Ma= 365.904 g

What mass of alum would you expect?

Question Parameters:

Beer can mass (aluminium metal ) = 16.5 g

% yield = 126 % = 1.26

Generally, the equation for the Mass of alum   is mathematically given as

M=Beer can mass * 1 g of  alum produce

M= 16.5 x 17.6

M= 290.4 g

therefore, the Mass of alum expected

Ma= % yield x mass of alum

Ma= 1.26 x 290.4

Ma= 365.904 g

In conclusion, the mass of alum  expected is

Ma= 365.904 g

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