[tex]\qquad \qquad\huge \underline{\boxed{\sf Answer}}[/tex]
let the required number be ' x '
Now, let's form a equation as per the question ~
[tex]\qquad \sf \dashrightarrow \: - \bigg(\dfrac{ 7}{3} \times 2 \bigg ) + x = \dfrac{3}{7} [/tex]
[tex]\qquad \sf \dashrightarrow \: - \dfrac{ 14}{3} + x = \dfrac{3}{7} [/tex]
[tex]\qquad \sf \dashrightarrow \: x = \dfrac{3}{7} + \dfrac{14}{3} [/tex]
[tex]\qquad \sf \dashrightarrow \: x = \dfrac{9 + 98}{21} [/tex]
[tex]\qquad \sf \dashrightarrow \: x = \dfrac{107}{21} [/tex]
