Respuesta :

The concentration of S2−in equilibrium with MnS(s) (sp=4. 6×10−14) and 0.083M Mn2+ is mathematically given as

[s^2-]=61.333*10^{-14}M

What is the concentration of S2−?

Generally, the equation for the solubility constant  is mathematically given as

Ksp=[Mn^2+][s^2-]

Therefore

4.6*10^{-14}=0.075*[s^2-]

[s^2-]=4500/0.075*10{-14}

[s^2-]=61.333*10^{-14}M

In conclusion, The concentration of S2−

[s^2-]=61.333*10^{-14}M

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