At the airport, ten people are waiting on standby. two seats become available, one first-class and one coach, There are 90 ways to fill the two seats.
It is given that there are ten people waiting on standby.
Two seats are available, One is first class and another one is coach.
It is required to find how many ways are there to fill the two seats.
A permutation can be defined as the number of ways a set can be arranged.
We have ten people and two seats in which only two people can seat out of ten.
It is a problem based on the permutation concept.
So for the first seat, there are 10 ways to fill the first seat
and for the second seat, there are [tex](10-1)[/tex] ways to fill the second seat.
If "P" is the number of ways we can assign the seats:
Then, P = 10×(10-1) = 10×9 = 90
Thus, there are 90 ways to fill the two seats.
Learn more about permutation here:
https://brainly.com/question/1216161
