Based on the inputList and the binarySearch, the value that will be returned by the call binarySearch above is 6.
With inputList = [0, 10, 30, 40, 50, 70, 70, 70, 70], the first call would be:
1st call = binarySearch(inputList, 0, 8, 70)
mid = 8 + (0/2)
= 4
if (70 is less then 50)
A second call would yield:
2nd call = binarySearch(inputList, 5, 8, 70)
mid = 13/2
= 6
if (70 = (70))
Return is 6 is the above holds so output is 6.
Find out more on Binary searches at https://brainly.com/question/21475482.