The solution of [tex]\rm log(2t+4)=log(14-3t)[/tex] is t=2
It is given that:
[tex]\rm log(2t+4)=log(14-3t)[/tex]
It is required to find the value of 't'.
It is another way to represent the power of numbers ie.
[tex]a^b=c\\log_ac=b[/tex]
We have:
[tex]\rm log(2t+4)=log(14-3t)[/tex] [tex]\rm (Taking \ log_1_0 \ base \ and \ removing \ the \ log_1_0 \ from \ both \ the\ side)[/tex]
We will get:
[tex]\rm 2t+4=14-3t\\\rm 5t=10\\\rm t=2[/tex]
Therefore the solution of [tex]\rm log(2t+4)=log(14-3t)[/tex] is t=2
Learn more about the Logarithm here.
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