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Ivan must choose a number between 55 and 101 that is a multiple of 4, 5, and 8. Write all the numbers that he could choose. If there is more than one number, separate them with commas.

Respuesta :

Solution:

1. Since the numbers must be divisible by 2 even numbers, all odd numbers are ruled out because odd numbers are not divisible with even numbers.

In this case, the numbers that are possible are:

  • 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98, 100

2. Since the numbers must be divisible by 5, it rules out a few more numbers.

In this case, the remaining numbers are:

  • 60, 70, 80, 90, 100

We can clearly tell that the only number that is divisible by 8, 5, and 4 is 80.

Thus, 80 is the number.

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