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Calculate the wave speed (in m/s) for the following waves:


a) A sound wave in steel with a frequency of 500 Hz and a wavelength of 3.0 meters. (2pts)







b) a ripple on a pond with a frequency of 2 Hz and a wavelength of 0.4 meters. (2pts)









Calculate the wavelength (in meters) for the following waves:



A wave on a slinky spring with a frequency of 2 Hz travelling at 3 m/s. (2pts)







An ultrasound wave with a frequency 40,000 Hz travelling at 1450 m/s in fatty tissue. (2pts)









Calculate the frequency (in Hz) for the following waves:



A wave on the sea with a speed of 8 m/s and a wavelength of 20 meters. (2pts)







A microwave of wavelength 0.15 meters travelling through space at 300,000,000 m/s. (2pts)

Respuesta :

Answer: A : 250 is the answer

B; The frequency of a wave is the number of complete oscillations (cycles) made by the wave in one second.

Instead, the wavelength is the distance between two consecutive crests (highest position) or 2 troughs (lowest position) of the wave.

In this problem, we are told that the leaf does two full up and down bobs: this means that it completes 2 full cycles in one second. Therefore, its frequency is

where Β is called Hertz (Hz). So, the correct answer is

Explanation:

#Wavespeed

#1

[tex]\\ \rm\Rrightarrow v=\nu\lambda=500(3)=1500m/s[/tex]

#2

[tex]\\ \rm\Rrightarrow v=2(0.4)=0.8m/s[/tex]

#Wavelength

#1

[tex]\\ \rm\Rrightarrow \lambda=\dfrac{v}{\nu}=\dfrac{3}{2}=1.5m[/tex]

#2

[tex]\\ \rm\Rrightarrow \lambda= \dfrac{1450}{40000}=0.03625m[/tex]

#Frequency

[tex]\\ \rm\Rrightarrow \nu=\dfrac{v}{\lambda}=\dfrac{8}{20}=0.4Hz[/tex]

#2

[tex]\\ \rm\Rrightarrow \nu=\dfrac{3\times 10^8}{15\times 10^{-2}}=0.2\timee 10^{10}=2\times 10^9Hz[/tex]