The height from which the engineer needs to release the ball is : Â 11.811 m
Given data:
Mass of wrecking ball = 52 kg
velocity of wrecking ball ( Vf ) = 12.3 m/s
Initial velocity of ball ( Vi ) = 0 m/s
final height ( hf ) = 4.1 m
Applying the principle of energy conservation
 Initial energy = final energy
= 1/2 mV²i  + mghi =  1/2 mV²f  + mghf  ----- ( 1 )
given that Vi = 0 also cancelling out m from both sides
Equation ( 1 ) becomes
=  0  +  hi  =  V²f / 2g  + hf
therefore :  hi = ( 12.3 )² / 2 * 9.81  + 4.1
            = 151.29 / 19.62  + 4.1
            = 11.811 m
Hence we can conclude that The height from which the engineer needs to release the ball is : Â 11.811 m
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