Respuesta :
Photo is attached.
Sorry my writing is so messy, but basically I found all possible zeros by finding the factors of 24:
(Positive or negative) 1,2,3,4,6,8,12,24
Then, using remainder theorem (when you plug potential zeros into the x values to see if the equation will equal zero) I found out that 1 made the equation equal zero, and therefore was a zero.
Then I used synthetic division to make the equation smaller (I also used 2 because I found out that it was a zero using remainder theorem, same as how I found out 1)
Once I divided it small enough to factor, I simply factored it to find the last 2 zeros
(I didn’t explain everything 100% bc I don’t know how much of this you have learned so if you want clarification on something let me know)
Sorry my writing is so messy, but basically I found all possible zeros by finding the factors of 24:
(Positive or negative) 1,2,3,4,6,8,12,24
Then, using remainder theorem (when you plug potential zeros into the x values to see if the equation will equal zero) I found out that 1 made the equation equal zero, and therefore was a zero.
Then I used synthetic division to make the equation smaller (I also used 2 because I found out that it was a zero using remainder theorem, same as how I found out 1)
Once I divided it small enough to factor, I simply factored it to find the last 2 zeros
(I didn’t explain everything 100% bc I don’t know how much of this you have learned so if you want clarification on something let me know)
Answer:
x=1 or x=2 or x=3 or x=4
Step-by-step explanation:
x4−10x3+35x2−50x+24=0
Step 1: Factor left side of equation.
(x−1)(x−2)(x−3)(x−4)=0
Step 2: Set factors equal to 0.
x−1=0 or x−2=0 or x−3=0 or x−4=0
x=1 or x=2 or x=3 or x=4