Mr. steiner purchased a car for about $14,000. assuming his loan was
compounded monthly at an interest rate of 4.9% for 72 months:
p=
r=
n=
t=
a. how much will he have paid total?
b. how much more did he pay than the price of the car?

Respuesta :

Using compound interest, it is found that:

a) He will have paid $18,774 in total.

b) He paid $4,774 more than the price of the car.

What is compound interest?

The amount of money earned, in compound interest, after t years, is given by:

[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]

In which:

  • A(t) is the amount of money after t years.
  • P is the principal(the initial sum of money).
  • r is the interest rate(as a decimal value).
  • n is the number of times that interest is compounded per year.
  • t is the time in years for which the money is invested or borrowed.

In this problem, the parameters are:

[tex]P = 14000, r = 0.049, n = 12, t = \frac{72}{12} = 6[/tex].

Item a:

[tex]A(t) = P\left(1 + \frac{r}{n}\right)^{nt}[/tex]

[tex]A(6) = 14000\left(1 + \frac{0.049}{12}\right)^{12 \times 6}[/tex]

[tex]A(6) = 18774[/tex]

He will have paid $18,774 in total.

Item b:

18774 - 14000 = $4,774.

He paid $4,774 more than the price of the car.

More can be learned about compound interest at https://brainly.com/question/25781328