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A floor whose length and width is 50 m and 40 m respectively needs to be covered by rectangular tiles. The dimension of each tile is 1 m x 2 m. Find the total number of tiles that would be required to fully cover the floor.
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hello people A floor whose length and width is 50 m and 40 m respectively needs to be covered by rectangular tiles The dimension of each tile is 1 m x 2 m Find class=

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fieryanswererft

Answer:

1000 tiles required.

explanation:

  • area of rectangle = Length * Width

Tiles dimension:

  • length: 1 meter
  • width: 2 meter

Floor dimension:

  • length: 50 meter
  • width: 40 meter

Area of floor:

Length * Width

50 * 40

2000 m²

Area of each tile:

Length * Width

1 * 2

2 m²

Number of tiles required = Area of floor ÷ Area of each tile

→ tiles = 2000/2

→ tiles = 1000

See below.

1000

area of rectangle = width x length

Given: width of floor = 40 m length of floor = 50 m ⇒ area of floor = 40 x 50 = 2000 m²

width of tile = 1 m length of tile = 2 m ⇒ area of tile = 1 x 2 = 2 m² Number of tiles needed = area of floor ÷ area of one tile                                        = 2000 ÷ 2                                        = 1000

I tried.

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