Answer:
length= 52 feet,
width= 15 feet
Step-by-step explanation:
[tex]\textcolor{steelblue}{\text{\textcircled{1} Define the variables}}[/tex]
Let the length and the width of the rectangle bs L and W feet respectively.
L= 4W -8 -----(1)
Perimeter of rectangle= 2(length +width)
2(L +W)= 134
Divide both sides by 2:
L +W= 67 -----(2)
[tex]\textcolor{steelblue}{\text{\textcircled{2} Solve for one variable}}[/tex]
Substitute (1) into (2):
4W -8 +W= 67
5W -8= 66
5W= 67 +8
5W= 75
W= 75 ÷5
W= 15
[tex]\textcolor{steelblue}{\text{\textcircled{3} Solve for the other variable}}[/tex]
Substitute W= 15 into (1):
L= 4(15) -8
L= 60 -8
L= 52
[tex]\textcolor{steelblue}{\text{\textcircled{4} Write concluding statement}}[/tex]
Thus, the rectangle's length is 52 feet, and its width is 15 feet.
