Answer:
Since the diagonal is the maximum dimension in a square, if the length of the diagonal is less than the diameter of the circle which is 9cm, then the square can fit inside the circle.
Step-by-step explanation:
Given:
A circle that has a diameter of 9cm
Square that has a side length of 5cm
Find:
First, find the length of the diagonal of the square.
Solve:
Let D represents the length of the diagonal of square
Using the Pythagora's Theorem
D² = side² + side²
D² = 2side²
Since the length of square is equal to 5cm then,
D² = 2 × 5²
D² = 50
√D² = √50
D = √25 ×2
D = 5√2
D = 7.07106781187
D = 7.07
We can see that the length of the diagonal of the square is less than the diameter of the circle, so the square can fit inside the circle.
