Nashiexx
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Need help please!

1.) m varies directly as a and b; m=10 when a=4 and b=7. Find m when a=11 and b=8.

2.) q varies jointly as x and y. Find q when x=2 and y=5, given that q=90 when x=3 and y=5.

3.) F varies jointly as x and y. If F=1 when x=1/2 and y=1/3, find F when x=2 and y=3.

4.) Let x be proportional to p and q^2, and inversely proportional to r^3. If x=9 when p=4, q=9, and r=3, find x if p=6, q=2, and r=5.

Respuesta :

itsashleynicole04

Answer:

4) v=kx^2/y^3

2= k(4^2)/(3^3)

2 =k16/27

k = 2(27/16) = 27/8

v = (27/8)(3^2)/(2^3 = (27/8)(9/8) = 243/64

v = 243/64 when x=3 and y=2

Step-by-step explanation:

here

F varies jointly as x and y and the value of x is 3 and y is 2.

We have given that,

1.) m varies directly as a and b  m=10 when a=4 and b=7. Find m when a=11 and b=8.

What is the formula?

v=kx^2/y^3

2= k(4^2)/(3^3)

2 =k(16/27)

k = 2(27/16)

k = 27/8

v = (27/8)(3^2)/(2^3)

= (27/8)(9/8)

= 243/64

v = 243/64 when x=3 and y=2.

Therefore we get the value of x is 3 and y is 2.

To learn more about the inverse value visit:

https://brainly.com/question/3831584

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