Respuesta :

EuphoricMoon

Answer:

[tex]Molecular \: mass \: of \: MgSO_{4}.2H_{2}O\:, \\ \\ ⇝ 24 + 32 + 16 \times 4 + 2(2 \times 1 + 46) \\ \\ ⇝ 24 + 32 + 64 + 36 \\ \\ ⇝156 \: u[/tex]

[tex]\bold\pink{Percentage \: of \: substance \: in \: compound} \\ \\ \bold\pink{⇝ \frac{mass \: of \: substance}{mass \: of \: compound} \times 100}[/tex]

[tex]\% \: age \: of \: Sulphur \: (S) = \frac{32}{156} \times 100 \\ \\ ⇝0.205 \times 100 \\ \\ \fbox\blue{\:⇝ 20.5\%\:}[/tex]

hope helpful ~

Answer:

20.51%

Explanation:

Mass of S = 32g

Mass of MgSO₄ x 2H₂O = 24 + 32 + 64 + 36 = 56 + 100 = 156

  • %S = 32/156
  • %S = 8/39
  • %S = 20.51%

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