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A, B & C form the vertices of a triangle.
∠ CAB = 90°,
∠ ABC = 51° and AB = 8.6.
Calculate the length of BC rounded to 3 SF.

Respuesta :

Answer:

BC ≈ 13.7

Step-by-step explanation:

using the cosine ratio in the right triangle

cos51° = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{AB}{BC}[/tex] = [tex]\frac{8.6}{BC}[/tex] ( multiply both sides by BC )

BC × cos51° = 8.6 ( divide both sides by cos51° )

BC = [tex]\frac{8.6}{cos51}[/tex] ≈ 13.7 ( to 3 sf )

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