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A 35.0 - g bullet moving at 475 m/s strikes a 2.5 - kg bag of flour at rest on ice. The bullet passes through the bag and exits it at 275 m/s. How fast is the bag moving when the bullet exits?

please show work. ​

Respuesta :

Snor1ax

Answer: 2.8 m/s

Explanation:

Because momentum is conserved, the momentum obtained by the bag matches the momentum lost by the bullet.

The momentum gained by the bag = MV = 2.5V

Loss in momentum of bullet = m(u-v) = 0.035(475 - 275) = 7 kg*m/s

2.5V = 7

V = 7 /2.5 = 2.8 m/s

Therefore, the speed of the bag is 2.8 m/s

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