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A proton moves north with a speed of 3 x 10^6 m/s. A 5 Tesla magnetic field is directed west. Determine the magnitude and direction of the magnetic field on the proton.

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onyebuchinnaji

The magnitude of magnitude force on the proton is 2.4 x 10⁻¹² N.

Magnitude of magnetic force on the proton

The magnitude of magnitude force on the proton is calculated as follows;

F = qvB sinθ

where;

  • q is the charge of the proton
  • v is the speed of the proton
  • B is the magnitude of the magnetic filed
  • θ is the angle between the field and speed

Substitute the given parameters and solve for the magnetic force.

F = (1.6 x 10⁻¹⁹) x (3 x 10⁶) x (5) X(sin90)

F = 2.4 x 10⁻¹² N

Thus, the magnitude of magnitude force on the proton is 2.4 x 10⁻¹² N.

Learn more about magnetic force here: https://brainly.com/question/13277365

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