Let
[tex]A(0,3) B(1,1)[/tex]
Step 1
Find the slope of the line
we know that
the formula to calculate the slope between two points is equal to
[tex]m=\frac{(y2-y1)}{(x2-x1)}[/tex]
substitute the values
[tex]m=\frac{(1-3)}{(1-0)}[/tex]
[tex]m=\frac{(-2)}{(1)}[/tex]
[tex]m=-2[/tex]
Step 2
Find the y-intercept
we know that
the y-intercept is the value of y when the value of x is equal to zero
in this problem the y-intercept is the point [tex]A(0,3)[/tex]
Step 3
Find the equation of the line into slope-intercept form
we know that
the equation of the line into slope-intercept form is equal to
[tex]y=mx+b[/tex]
we have
[tex]m=-2[/tex]
[tex]b=3[/tex] -----> b is equal to the y-coordinate of the y-intercept
substitute
[tex]y=-2x+3[/tex]
therefore
the answer is the option A
[tex]y=-2x+3[/tex]