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An aircraft is in a steady climb, at an airspeed of 100 knots, and the flight path makes a positive 10 degree angle with the horizontal. Find the Rate of Climb.

Respuesta :

batolisis

The rate of climb of the aircraft in a steady climb making a 10 degree angle with the horizontal is : 17.36 knots

Given data

Airspeed = 100 knots

Angle with the horizontal ( ∅ ) = 10°

Determine the rate of climb of the aircraft

we will apply the formula below

Vy ( rate of climb ) = Airspeed * sin ∅

                              = 100 * sin ( 10 )

                              = 17.36 Knots

Hence we can conclude that rate of climb of the aircraft in a steady climb is : 17.36 knots.

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