The general equation of the sine function is [tex]\rm y= 2sin(2(x-\pi)[/tex]. The sine and cosine of an acute angle are utilized to find the angle of the triangle.
The sine and cosine of an angle are trigonometric functions. In the context of a right triangle, the sine and cosine of an acute angle are used to find the angle of the triangle.
The standard general equation of a sine function is given as;
[tex]\rm y= AsinB(x-C)+D[/tex]
Where A denotes the amplitude, B is the frequency, D is the vertical shift and C is the phase shift.
The given data in the problem is;
A is the amplitude= 2
B is the frequency=2
D is the vertical shift =0
C is the phase shift.=[tex]\pi[/tex]
The general equation is found as;
[tex]\rm y= 2sin(2(x-\pi)[/tex]
Hence the general equation of the sine function is [tex]\rm y= 2sin(2(x-\pi)[/tex].
To learn more about the sin function refer to the link;
https://brainly.com/question/6826226
