The joint probability distribution of the number x of cars and the number y of buses per signal cycle at a proposed left-turn lane is displayed in the accompanying joint probability table.

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MrRoyal MrRoyal · Answer 1 · 2022-03-31T18:31:18+02:00

The joint probability distribution combines the probabilities of x and y

The probability that there is exactly one car and exactly one bus during a cycle is 0.020

The complete question requests that the probability that there is exactly one car and exactly one bus during a cycle be calculated.

This means that, we check the table where the values of x and y are 1.

i.e.:

P(x,y) = P(1,1)

From the complete table, we have:

P(x,y) = P(1,1) = 0.020

Hence, the probability that there is exactly one car and exactly one bus during a cycle is 0.020