Answer:
Line [tex]a[/tex] and line [tex]c[/tex] are parallel to each other.
Line [tex]b[/tex] is perpendicular to line [tex]a[/tex].
Line [tex]b[/tex] is perpendicular to line [tex]c[/tex].
Step-by-step explanation:
Rewrite the equation of each line in the slope-intercept form [tex]y = m\, x + b[/tex] to find the slope [tex]m[/tex] of that line.
In the slope-intercept form, [tex]y[/tex] need to be on the left-hand side of the equation while [tex]x[/tex] need to be on the right-hand side. The coefficient of [tex]y[/tex] must be [tex]1[/tex]. The slope of the line would then be equal to the coefficient of [tex]x[/tex].
For example, the equation of line [tex]a[/tex] could be rewritten in slope-intercept form as [tex]y = 3\, x + 5[/tex]. The coefficient of [tex]x[/tex] is [tex]3[/tex], so the slope of this line would be [tex]m_{a} = 3\![/tex].
Similarly, rewrite to obtain the the slope-intercept equation of line [tex]b[/tex]: [tex]y = (-1/3)\, x + (2/3)[/tex]. The slope of this line would be [tex]m_{b} = (-1/3)[/tex].
The equation of line [tex]c[/tex] is already in slope-intercept form. The slope of that line would be [tex]m_{c} = 3[/tex].
Let [tex]m_{1}[/tex] and [tex]m_{2}[/tex] denote the slopes of two lines in a Cartesian plane.
In this question, the slope of line [tex]a[/tex] and line [tex]c[/tex] are the same: [tex]m_{a} = m_{c}[/tex]. Thus, line [tex]a\![/tex] and line [tex]c\![/tex] would be parallel.
The product of the slopes of line [tex]a[/tex] and line [tex]b[/tex] is [tex]m_{a}\, m_{b} = 3 \times (-1/3) = (-1)[/tex]. Thus, line [tex]a\![/tex] and line [tex]b[/tex] are perpendicular to each other.
Similarly, line [tex]b[/tex] and line [tex]c[/tex] are perpendicular to each other because the product of their slopes is [tex](-1)[/tex].
