Find H
[tex]\\ \rm\rightarrowtail H^2=36^2+15^2[/tex]
[tex]\\ \rm\rightarrowtail H^2=39^2[/tex]
[tex]\\ \rm\rightarrowtail H=39[/tex]
Now
[tex]\\ \rm\rightarrowtail sinR=\dfrac{P}{H}=\dfrac{15}{39}=\dfrac{5}{13}[/tex]
[tex]\\ \rm\rightarrowtail cosR=\dfrac{B}{H}=\dfrac{36}{39}=\dfrac{12}{13}[/tex]
[tex]\\ \rm\rightarrowtail tanR=\dfrac{P}{B}=\dfrac{5}{12}[/tex]
[tex]\\ \rm\rightarrowtail sinT=\dfrac{36}{39}=\dfrac{12}{13}[/tex]
[tex]\\ \rm\rightarrowtail cosT=\dfrac{5}{13}[/tex]
[tex]\\ \rm\rightarrowtail tanT=\dfrac{12}{5}[/tex]
