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3. in a purity check for industrial diamonds, a 10.25 degrees carat (1carat = 0.2000g) diamond is heated to 74.21 °c and immersed in 26.05 g of water in a constant pressure calorimeter. the initial temperature of the water is 27.20 ^ c . the final temperature of the system is 27.65 °c. calculate the specific heat of the diamond.

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From the calculations, the specific heat capacity of diamond is 42.36  J/Kg/°C.

What is specific heat capacity?

The specific heat capacity is the heat absorbed or emitted when 1Kg of a susbtance is heated such that its temperature is increased by 1 K.

Now;

Mass of water = 26.05 g or 0.026 Kg

Mass of diamond = 2.05 g or 0.00205 Kg

specific heat capacity of water = 4200 J/Kg/°C

specific heat capacity of diamond = ?

Initial temperature of water =  27.20°C

Initial temperature of diamond =74.21 °c

Final temperature of the diamond and water = 27.65 °c

Heat lost by diamond = heat gained by water

mcdT = mcdT

0.00205 Kg * c * ( 74.21 °c - 27.65 °c ) = 0.026 Kg * 4200 J/Kg/°C * (27.65 °c - 27.20°C)

0.116c = 4.914

c = 4.914/0.116

c = 42.36  J/Kg/°C

Learn more about specific heat capacity: https://brainly.com/question/2530523

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