The growth in Nora's salary illustrates a geometric progression
The total amount earned over the 21 years is $1147059
The given parameters are:
Initial salary, a = 40000
Rate, r = 1 + 3% = 1.03
Number of years = 21
The sum of n terms of a geometric progression is represented as:
Sn = a((r^n) - 1)/(r - 1)
So, we have:
S21 = 40000 * ((1.03^21) - 1)/(1.03 - 1)
Evaluate
S21 = 1147059
Hence, the total amount earned is $1147059
Read more about geometric progressions at:
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