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What is the magnitude of the net torque on the wheel due to these three forces for an axis perpendicular to the wheel and passing through its center?.

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onyebuchinnaji

The magnitude of the net torque on the wheel due to these three forces for an axis perpendicular to the wheel and passing through its center is

¹/₂MR³a.

Net torque on the wheel

The net torque on the wheel is determined from the moment of inertia of the pulley and the angular acceleration of the pulley.

∑τ = Iα

where;

  • I is moment of inertia of pulley
  • α is angular acceleration of the pulley

Let the pulley be a solid uniform disk, the moment of inertia of the axis perpendicular to the wheel and passing through its center is calculated as;

I = ¹/₂MR²

τ = ¹/₂MR²α

τ = ¹/₂MR²(aR)

τ = ¹/₂MR³a

where;

  • a is the acceleration of the pulley due to the applied force.

Thus, the magnitude of the net torque on the wheel due to these three forces for an axis perpendicular to the wheel and passing through its center is ¹/₂MR³a.

Learn more about moment of inertia here: https://brainly.com/question/3406242

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