Respuesta :
The valur of energy of formation ΔGf of H₂O is -228.6 kJ/mol.
How we calculate ΔG ?
ΔG of any reaction will be calculated as:
ΔG = Sum of ΔG of products - Sum of ΔG of reactants
Given chemical reaction is:
4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(g)
For this reaction, ΔG will be calculated as:
ΔG = [ΔGf 4(NO) + ΔGf 6(H₂O)] - [ΔGf 4(NH₃) + ΔGf 5(O₂)]
Given that:
ΔG = -957.9 kJ
ΔGf of NH₃ = -16.66 kJ/mol
ΔGf of NO = 86.71 kJ/mol
ΔGf of O₂ = 0 (because it is present in elemental form)
ΔGf of H₂O = let x (to find)
On putting all these values on the above equation, we get
-957.9 = [4(86.71) + 6(x)] - [4(-16.66) + 5(0)]
-957.9 = 346.84 + 6x + 66.64
6x = -957.9 - 346.84 - 66.64
6x = -1,371.38
x = -228.56 = -228.6 kJ/mol
Hence, correct option is (1) i.e. -228.6 kJ/mol.
To know more about ΔG, visit the below link:
https://brainly.com/question/2507189
