Respuesta :

[tex](\stackrel{a}{-35}~~,~~\stackrel{b}{-12})\qquad \impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c = \sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{(-35)^2+(-12)^2}\implies c=\sqrt{1225+144}\implies c=\sqrt{1369} \\\\\\ \underline{c=37}~\hspace{10em}sin(\theta )=\cfrac{\stackrel{opposite}{-12}}{\underset{hypotenuse}{37}}[/tex]