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100 BRAINLY POINTS!!!

Each point on the scatter plot below represents the number of hours a student studied for a test and the
student's test scores.

Which equation is the closest approximation to the line of best fit?

A. y = -10x + 92

B. y = 6x + 59

C. y = 10x + 45

D. y = 15x + 30

PLEASE HURRY CUH

EXPLAIN YOUR ANSWER
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100 BRAINLY POINTS Each point on the scatter plot below represents the number of hours a student studied for a test and the students test scores Which equation class=

Respuesta :

Let's take 1 of x axis from plot (It has three values in y so much useful)

#A

  • y=-10x+92=-10+92=82

#B

  • y=6x+59=6+59=65

#C

  • y=10x+45=10+45=55

#D

  • y=15x+30=15+30=45

A and D are out of radar .Now we need to find most approx between B and C

Go to 2 now.(Same 3 values)

#B

  • y=12+59=71

#C

  • y=20+45=65

65 lies between 60 and 70 ,most approximately equal .

Option C is correct

semsee45

Answer:

C [tex]y=10x+45[/tex]

Step-by-step explanation:

Line of best fit (trendline) : a line through a scatter plot of data points that best expresses the relationship between those points.

All the given options for the line of best fit are linear equations.

Therefore, we can add the line of best fit to the graph (see attached), remembering to have roughly the same number of points above and below the line.

Linear equation:  [tex]y=mx+b[/tex]

(where [tex]m[/tex] is the slope and [tex]b[/tex] is the y-intercept)

From inspection of the line of best fit, we can see that the y-intercept (where x = 0) is approximately 45.  So this suggests that option C is the solution.

We can also see that the line of best fit appears to be the same distance from points (3, 75) and (4, 85).  So we can use the slope formula with these points to give a rough estimate of the slope of the line of best fit:

[tex]\sf{slope=\dfrac{y_2-y_1}{x_2-x_1}}=\dfrac{85-75}{4-3}=10[/tex]

Therefore, this concurs that C is the solution and that the closet approximation to the line of best fit is [tex]y=10x+45[/tex]

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