The solution to the given expression is (6x^4-40)(36x^8+48x^4+16)
We have the following expression
[tex]=216x^{12}-64[/tex]
we can also write it as
[tex]=(6x^4)^3-(4)^3[/tex]
Now from the formula
[tex]a^3-b^3=(a-b)(a^2+b^2+2ab)[/tex]
[tex](6x^3)-(4)^3=(6x^4-4)((6x^4)^2+(4)^2+(2\times 6x^4\times 4)[/tex]
[tex](6x^3)-(4)^3=(6x^4-4)((6x^8+16+(48x^4))[/tex]
[tex](6x^3)-(4)^3=(6x^4-4)(6x^8+48x^4+16)[/tex]
Thus the solution to the given expression will be
[tex](6x^4-40)(36x^8+48x^4+16)[/tex]
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