The confidence interval for the sample proportion is [tex]CI = 0.16 \pm 0.0545[/tex]
The formula for calculating the confidence interval for proportion is expressed as:
[tex]p \pm z\sqrt{p(1-p)/n[/tex]
p is the proportion
z is the z score at 99% interval
n is the sample size
Given the following parameters
[tex]p=\frac{47}{300} = 0.16\\z=2.576\\n=300[/tex]
Substitute the values
[tex]CI = 0.16 \pm 2.576\sqrt{0.16(0.84)/300}\\CI=0.16\pm2.576(0.02116)\\CI = 0.16 \pm 0.0545[/tex]
Hence the confidence interval for the sample proportion is [tex]CI = 0.16 \pm 0.0545[/tex]
Learn more on confidence interval here: https://brainly.com/question/15712887
