The molar concentration of benzene is 0.05mol/L
Data;
molar mass of benzene = 78g/mol
molar mass of ethanol = 46g/mol
mole fraction of benzene is
[tex]mole fraction = \frac{moles of benzene}{total mole}[/tex]
Let's substitute the values and find the mole fraction of benzene
[tex]_yC_6H_6 = \frac{\frac{0.005}{78} }{(\frac{0.005}{78})+ (\frac{1-0.005}{46}) }\\ _yC_6H_6 = 0.00295[/tex]
The density of benzene given is 789 kg/m^3
Molar concentration of the solution is
[tex]M = \frac{789}{0.046} = 17.15Kmol/m^3[/tex]
The concentration of benzene is the product of mole fraction and the molar concentration of the solution
[tex]M = 0.00295 * 17.152 = 0.05Kmol/m^3= 0.05mol/L[/tex]
The molar concentration of benzene is 0.05mol/L
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